The probability of selecting a red ball
Webb3 okt. 2024 · The probability of selecting a red ball at random from the jar that contains only red, blue and orange balls is 1/4. asked Apr 21, 2024 in Probability by Vevek01 … WebbTherefore, the probability of selecting a red ball followed by an orange ball if the selection is done with replacement is 8/75. Advertisement Advertisement New questions in Math. A box contains 8 red balls, 3 orange balls, and 4 yellow balls.
The probability of selecting a red ball
Did you know?
Webb12 dec. 2014 · Find the probability that A selects the red ball. (A draws the first ball, then B, and so on. There is no replacement of the balls drawn.) How do I calculate this probability? I tried using the total probability rule without success. I used the … WebbA probability of selecting a red ball at random from a jar that contains only red,blue and orange is 1 4 .The probability of selecting a blue ball at random from the same jar is 1 3 .If the jar contains 10 orange balls,find the total number of balls in the jar. Solution Given, a jar contains red,blue and orange balls. Let the number of red balls=x
Webb10 mars 2016 · the total number of balls is equal to number of red balls + blue + Orange balls . probability of getting a red ball is 1/4 probability of selecting a blue ball is 1/3 the … Webb18 nov. 2010 · A ball is selected and the color noted. Then it is replaced. A second ball is selected and its color noted. Find the probability of getting a red ball and a blue ball. asked by Maryan November 18, 2010 7 answers If you want them in that order prob = (3/10) (2/10) = 6/100 = 3/50 If the order does not matter, that is, it could RB or BR
WebbAnswer (1 of 3): I don’t mean to be picky, but it’s always important with questions like this to state the assumptions explicitly. The unstated assumption is that all the balls are … WebbTherefore, the probability of selecting a red ball followed by an orange ball if the selection is done with replacement is 8/75. Advertisement Advertisement New questions in Math. …
WebbA bag contains 6 red balls and 4 green balls. You plan to select 3 balls at random. Determine the probability of selecting 3 green balls. The problem is to be done without replacement. Use combinations to determine the probability. The probability is (Type an integer or a simplified fraction.) Question: A bag contains 6 red balls and 4 green ...
WebbS1 Probability PhysicsAndMathsTutor.com. 1. An experiment consists of selecting a ball from a bag and spinning a coin. The bag contains 5 red balls and 7 blue balls. A ball is selected at random from the bag, its colour is noted and then the ball is returned to the bag. When a red ball is selected, a biased coin with probability . 3 2 irr by sectorWebbFinal answer. A bag contains nine yellow balls, seven green balls, and four red balls Find the .probability of selecting four green balls 20C49C4 ⋅A None of these.B 20C47C4 ⋅ C 20C49C4 + 20C47C4 + 20C44C4 ⋅ D 20C127C4 ⋅ E. portable blender usb rechargeableWebbThe probability to randomly select two red balls from bag B is `4/6*3/5 = 12/30` . The probability to randomly select one red ball and one green ball from bag B is `4/6*2/5 = … portable blender walmartWebb20 okt. 2024 · A bag of the same size small balls contains 6 blue - Gauthmath. Math Resources /. algebra /. equation /. A bag of the same size small balls contains 6 blue … portable blender with travel lidWebb(a) To calculate the probability of selecting one red and two black balls, we can use the formula P (one red and two black) = P ( r e d) × P ( b l a c k) × P ( b l a c k) = 1 4 × 7 12 × 7 12 = 49 576 ≈ 0.0851 So the probability of selecting one red and two black balls is approximately 0.0851. View the full answer Step 2/3 Step 3/3 Final answer portable blackstone griddle with lidWebba) P (Two red) = P (Red)*P (Red after one is drawn) = (5/10) (4/9) = 20/180 = 1/9 b) P (One blue and one yellow) = P (blue) * P (yellow after one draw) = (3/10) (2/9) = 6/90 = 1/15 c) P (Two yellow) = P (yellow)*P (yellow after one is drawn) = (2/10) (1/9) = 2/90 = 1/45 d) irr cnyWebbThe probability of selecting a red ball at random from a jar that contains only red, blue and orange balls is 1/4 . The probability of selecting a blue ball at random from the same jar … irr cbms law